Solve the inequalities in Exercises 5 to 16 for real x:

3x – 7 > 5x – 1


It is given in the question that,

3x – 7 > 5x – 1


Adding 7 to both the sides,


3x – 7 + 7 > 5x – 1 + 7


3x> 5x + 6


Subtracting 5x from both the sides,


3x – 5x > 5x + 6 – 5x


-2x > 6


Dividing both sides by -2



x < -3


The solutions of the given inequality are defined by all the real numbers less than -3.


Thus, (-∞, -3) is the required solution set.


6
1