Solve the inequalities in Exercises 5 to 16 for real x:
3 (2 – x) ≥ 2 (1 – x)
It is given in the question that,
3 (2 – x) ≥ 2 (1 – x)
6 – 3x ≥ 2 – 2x
Adding 2x to both the sides,
6 – 3x+ 2x ≥ 2 – 2x+ 2x
6 – x≥ 2
Subtracting 6 from both the sides,
6 – x – 6 ≥2 – 6
- x ≥-4
x ≥ 4
∴ The solutions of the given inequality are defined by all the real numbers greater than or equal to 4.
Thus, [4, ∞) is the required solution set.