Solve the inequalities in Exercises 5 to 16 for real x:

37 – (3x + 5) ≥ 9x – 8 (x – 3)

We have,

37 - (3x + 5) ≥ 9x - 8 (x - 3)

= 37 - 3x – 5 ≥ 9x - 8x + 24

= 32 - 3x ≥ x + 24

= 32 - 24 ≥ x + 3x

= 8 ≥ 4x

= 2 ≥ x

∴ All the real numbers of x which are less than or equal to 2 are the solutions of the given inequality

Hence, will be the solution for the given inequality