Show that 9n+1 – 8n – 9 is divisible by 64, whenever n is a positive integer.
In order to show that 9n+1 – 8n – 9 is divisible by 64,
we have to prove that
9n+1 – 8n – 9 = 64k, where k is some natural number
Now,
9n+1 = (1+8)n+1
We know that-

putting a =1, b = 8, and n = n+1








Hence,

Taking out (8)2 from right side, we get-



where  is a natural number
 is a natural number
Thus, 9n+1 – 8n – 9 is divisible by 64.
Hence Proved.