In the expansion of (1 + a)m+n, prove that coefficients of am and an are equal.
The general term Tr+1 in the binomial expansion is given by Tr+1 = nCr an-r br
Here n= m+n , a = 1 and b= a
Putting the values in the general form
Tr+1 = m+nCr 1m+n-r ar
= m+nCr ar………….1
The coefficient of am is & the coefficient of an is
ar = am an = ar
⇒ r=m ⇒ n =r
Putting r = m in 1 & putting r= n in 1
Tm+1= m+nCm1m+n-m amTn+1 = m+nCn1m+n-n an
&
&
The coefficient of am and an are same i.e.;
Hence proved.