A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
Given,
Initial velocity, u = 0
Final velocity, v =?
Acceleration due to gravity, g = 9.8 m/s2
Height, h = 19.6 m
We know that,
v2 = u2 + 2gh
= (0)2 + 2 × 9.8 × 19.6
= 19.6 × 19.6
= (19.6)2
= 19.6 m/s
Therefore, its final velocity just before touching the ground is 19.6 m/s.