Write the value of k for which the system of equations x + y – 4 = 0 and 2x + ky – 3 = 0 has no solution.
Given:
Equation 1: x + y = 4
Equation 2: 2x + ky = 3
Both the equations are in the form of :
a1x + b1y = c1 & a2x + b2y = c2 where
a1 & a2 are the coefficients of x
b1 & b2 are the coefficients of y
c1 & c2 are the constants
For the system of linear equations to have no solutions we must have
………(i)
According to the problem:
a1 = 1
a2 = 2
b1 = 1
b2 = k
c1 = 4
c2 = 3
Putting the above values in equation (i) we get: