If S 1 is the sum of an arithmetic progression of 'n' odd number of terms and S 2 the sum of the terms of the series in odd places, then =

Question

Philoid · Accepted Answer

S₁ = (2a + (n–1) d)

Out of these odd numbers of terms, there are terms in odd places

S₂ = (2a + ( –1) d)

Common difference of two odd places is 2d

S₂ = (2a + (n–1) d)

Now,

=

If S1 is the sum of an arithmetic progression of 'n' odd number of terms and S2 the sum of the terms of the series in odd places, then =