If Sr denotes the sum of the first r terms of an A.P. Then, S3n: (S2n — Sn) is
S2n = (2a + (2n–1) d)
Sn = (2a + (n–1)d)
S3n = (2a + (n–1)d)
S2n –Sn = (2a + (2n–1) d) –
(2a + (n–1)d)
= (2a + (n –1) d)
S3n: (S2n — Sn) = (2a + (n–1)d) :
(2a + (n –1) d)
= 3