The 9th term of an A.P. is 449 and 449th term is 9. The term which is equal to zero is
Here, a9 = 449
A449 = 9
Let a is the first term and d is the common difference of the AP
Given 9th term of AP = 499
a + 8d = 499 .....(1)
Again 499th term of AP = 9
a + 498d = 9 .....(2)
Now subtract equation 1 and 2, we get
a + 8d – (a + 498d) = 499 – 9
a + 8d – a – 498d = 499 – 9
–490d = 490
d = –490/490
d = –1
Put value of d in equation1, we get
a – 8 = 499
a = 499 + 8
a = 507
Let nth term is equal is to zero
a + (n–1)d = 0
507 – (n–1) = 0 (By putting value of a and d)
507 – n + 1 = 0
508 – n = 0
n = 508
So 508th term of AP is zero.