Two children are at opposite ends of an aluminium rod. One strikes the end of rod with a stone. Find the ratio of times taken by sound wave in air and in aluminium to reach the second child (Given: Speed of sound in air = 346 m/s; Speed of sound in aluminium = 6240 m/s)
Let, the length of aluminium rod is l.
Now, firstly we calculate the speed of sound in air.
We know that,
Speed of sound (in air) = ![]()
346 = ![]()
Time taken in air = 
 (i)
Now, speed of sound in aluminium.
We know that,
Speed of sound (in aluminium) = ![]()
6420 = ![]()
Time taken in aluminium = 
 (ii)
Now by dividing (i) and (ii), we get:
![]()
= 6420/346
= ![]()
Therefore, the ratio is 18.55:1