A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Giving g = 10 m s^-2 and speed of sound = 340 m s^-1.

Question

A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Giving g = 10 m s -2 and speed of sound = 340 m s -1 .

Philoid · Accepted Answer

Given,

Distance covered by stone, s = 500 m

Initial speed, u = 0

Time taken, t =?

Acceleration, g = 10 m/s²

We know that,

s = ut + gt²

500 = 0 × t + × 10 × t²

500 = 5 × t²

=

= 100

t =

Time, t = 10 s (i)

We know that,

Speed of sound =

340 =

Time taken by sound =

= 1.47 s (ii)

So, the required time at which splash is heard at the top = 10 s + 1.47

= 11.47 s

A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Giving g = 10 m s-2 and speed of sound = 340 m s-1.

A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Giving g = 10 m s^-2 and speed of sound = 340 m s^-1.