For some constants a and b, find the derivative of

Let f(x) =

⇒ f(x) = a²x⁴ + 2abx² + b²

So,

⇒

Since,

f’(x) = a² × 4x³ + 2ab × 2x + 0

= 4a²x³ + 4abx

∴ f’(x) = 4ax (ax² + b)