An analysis of monthly wages paid to workers in two firms A and B, belonging to the same industry, gives the following results:

(i) Which firm A or B pays larger amount as monthly wages?

(ii) Which firm, A or B, shows greater variability in individual wages?

Here

Mean monthly wages of firm A = 5253

No. of wage earners = 586

Total amount paid = 586 × 5253 = 3078258

Mean monthly wages of firm B = 5253

No. of wage earners = 648

Total amount paid = 648 × 5253 = 340 3944

(i) Hence the firm B pays larger amount as monthly wages.

(ii) Variance of firm A = 100

⇒ standard deviation (σ)= √100=10

Variance of firm B = 121

⇒ Standard deviation (σ)=√(121 )=11

Since the standard deviation is more in case of Firm B that means in firm B there is greater variability in individual wages.