The mean and variance of eight observations are 9 and 9.25, respectively. If six of the observations are 6, 7, 10, 12, 12 and 13, find the remaining two observations.
Let us assume the remaining two observations to be x and y respectively such that,
Observations: 6, 7, 10, 12, 12, 13, x, y.
∴ Mean,
60 + x + y = 72
x + y = 12 (i)
By using (i)
So, from equation (i) we have:
Thus, from (ii) and (iii), we have
2xy = 64 (iv)
Now by subtracting (iv) from (ii), we get:
x2 + y2 – 2xy = 80 – 64
x – y = 4 (v)
Hence, from equation (i) and (v) we have:
When x – y = 4 then x = 8 and y = 4
And, when x – y = - 4 then x = 4 and y = 8
∴ The remaining observations are 4 and 8