Given that
is the mean and
is the variance of n observations x1, x2, ...,xn.
Prove that the mean and variance of the observations ax1, ax2, ax3, ...., axn are
and
, respectively, ![]()
The given n observations in the question are x1, x2,…..xn
Also, mean = ![]()
And, variance = σ2
We know that,

According to the condition given in the question, if each of the observation is being multiplied by a and the new observation are yi the, we have:
yi = axi
![]()



![]()
Hence, mean of the observations ax1, ax2,…..axn is a![]()
Now, by substituting the values of xi and
in (i), we get:


Hence, the variance of the given observations ax1, ax2,….axn is a2σ2