Diameter of a circle is 26 cm and length of a chord of the circle is 24 cm. Find the distance of the chord from the center.
Given that diameter = 26cm
Radius = Diameter / 2 = 26 /2 = 13cm
So, OA = 13cm
And AB = 24 cm
We know that a perpendicular drawn from the center of a circle on its chord bisects
the chord.
∴ AP = PB = 12 cm
In the right angled ΔOAP using Pythagoras theorem,
⇒ OA2 = OP2 + AP2
⇒ 132 = OP2 + 122
⇒ 169 = OP2 + 144
⇒ OP2 = 25
⇒ OP = 5cm
So, the distance of chord from the center is 5cm.