Draw a quadrilateral in the Cartesian plane, whose vertices are (– 4, 5), (0, 7), (5, – 5) and (– 4, –2). Also, find its area.

Let ABCD be the given quadrilateral with vertices A(-4,5) , B(0,7), C(5.-5) and D(-4,-2). Plotting the points on the Cartesian plane and joining AB, BC, CD, AD gives us the required quadrilateral.

To find the area, draw diagonal AC

area (ABCD) = ar ( ∆ABC) + ar(∆ADC)

area ∆ with vertices ( x₁,y₁) , (x₂, y₂) and (x₃,y₃) is

unit²

unit²

Area ∆ ACD =

Since area cannot be negative area ∆ ACD =

Area (ABCD) =