Find the distance of the point (–1, 1) from the line 12(x + 6) = 5(y – 2).

Question

Philoid · Accepted Answer

Given equation of the line 12(x + 6) = 5(y – 2).

⇒ 12x + 72 = 5y – 10

⇒12x – 5y + 82 = 0 … (1)

Comparing equation (1) with general equation of line Ax + By + C = 0, we obtain A = 12, B = –5, and C = 82

Perpendicular distance (d) of a line Ax + By + C = 0 from a point (x₁, y₁) is given by

Given point (x₁, y₁) = (-1, 1)

∴ distance of point (–1, 1) from the given line

d = 5 units