Find the values of k for which the line (k–3) x – (4 – k2) y + k2 –7k + 6 = 0 is

Parallel to the x-axis,


The given equation of the


(k–3) x – (4 – k2) y + 6


If the given line is parallel to the x- axis, then


Slope of the given line = Slope of the x- axis.


The given line can be written as


(4 – k2) = (k–3) x + k2 –7k + 6 = 0


y = which is the form y = mx+c


Thus, Slope of the given line =


Slope of x- axis = 0


Then,


k – 3 = 0


k = 3


Therefore, if the given line is parallel to the x – axis, then the value of k is 3.


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