Find the equation of a line drawn perpendicular to the line through the point, where it meets the y-axis.

The equation of the given line is

This equation can also be written as 3x + 2y -12 = 0

which is of the form y = mx + c

Thus, Slope of the given line =

and Slope of line perpendicular to the given line =

Let the given intersects the y – axis at (0,6)

The equation of the line has a slope of and passes through point (0,6) is

=> 3y – 18 = 2x

=> 2x – 3y + 18 = 0

Therefore, the required equation of the line is 2x – 3y + 18 = 0.