A person standing at the junction (crossing) of two straight paths represented by the equations 2x – 3y + 4 = 0 and 3x + 4y – 5 = 0 wants to reach the path whose equation is 6x – 7y + 8 = 0 in the least time. Find equation of the path that he should follow.
The equations of the given lines are
2x-3y+4 = 0 --------------- (1)
3x+4y- 5 = 0 ---------------- (2)
6x – 7y + 8 = 0
The person is standing at the junction of the paths represented by lines (1) and (2).
So, on solving equations (1) and (2), we get,
x =
and y = ![]()
Then, the person is standing at point ![]()
The person can reach path (3) in the least time if he walks along the perpendicular line to (3) from point ![]()
Thus, slope of the line (3) = ![]()
Thus, Slope of the line perpendicular to line (3) = ![]()
The equation of the line passing through
and having a slope of
is given by
![]()
⇒ 6(17y-22) = -7(17x+1)
⇒ 102y – 132 = 119x -7
⇒ 119x + 102y = 125
Therefore, the path that the person should follow is 119x + 102y = 125.