In triangles ABC and DEF, AB = FD and A = D. The two triangles will be congruent by SAS axiom if


Given: ΔABC and ΔDEF, AB = FD and A = D


The two triangles will be congruent by SAS axiom if two sides including one angle of one triangle is equal to the another triangle.


Hence, AC = DE (As A is between AB and AC)


Option B is correct.

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