In Figure, AD is the bisector of BAC. Prove that AB > BD.


Given: AD is the bisector of BAC.

As AD is the bisector of BAC.


BAD = CAD …(1)


ADB > CAD (exterior angle of a triangle is greater than each of opposite interior angle)


Then ADB > BAD (from (1))


AB > BD (opposite sides to greater angle is greater)


Hence proved.


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