O is the circumcenter of the triangle ABC and D is the mid-point of the base BC. Prove that BOD = A.


Given: O is the circumcenter of the triangle ABC and D is the midpoint of BC.


To prove: BOD = A


Join OB and OC.


In ΔOBD and ΔCD:


OD = OD (common side)


DB = Dc (D is the midpoint of BC)


OB = OC (Both are radius of the circle)


By SSS congruence rule, ΔOBD ΔOCD.


BOD = COD = x (say) (By CPCT)


Since, angle subtended by an arc at the center of the circle is twice the angle subtended by it at any other point in the remaining part of the circle, we have:


2BAC = BOC


2BAC = BOD + DOC


2BAC = x + x


2BAC = 2x


BAC = x


BAC = BOD


Hence, proved.


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