The area of the isosceles triangle is cm2 if the perimeter is 11 cm and the base is 5 cm.


Given Perimeter = 11cm

And a = 5


As the triangle is isosceles, b = c


Perimeter = 11


a + b + c = 11


5 + b + b = 11


5 + 2b = 11


2b = 6


b = 3


So, we have a = 5, b = 3, c = 3


s = (a + b + c)/2


s = (5 + 3 + 3)/2 = 11/2


Area(Δ) = √s(s-a)(s-b)(s-c)


Area(Δ) =


Area(Δ) =


Area(Δ) = (5√11)/4cm2


Hence, the statement is True.


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