A right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface of the solid so formed.
As the right triangle is revolved about the side 8 cm, it forms a cone of height 8 cm and radius, 6 cm.
Then, volume of cone = 1/3 πr2h
Curved surface area of cone is given by
CSA = πrl = πr√(r2 + h2)
⇒ CSA = 22/7 × 6 √(62 + 82)
⇒ CSA = 22/7 × 6 × √100
⇒ CSA = 22/7 × 6 × 10
⇒ CSA = 188.57 cm2
Thus, volume of the cone is 301.71 cm3 and curved surface area of cone is 188.57 cm2.
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