Look at the Fig. 5.3. Show that length AH > sum of lengths of AB + BC + CD.


From the given figure, we have


AB+BC+CD =AD [AB, BC and CD are the parts of AD]


Here, AD is also the part of AH.


According to Euclid’s axiom, the whole is greater than the part i.e., AH > AD


So, length AH > sum of the lengths of AB+BC+CD.


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