The diameter of an inflated ball is 18 cm. How many cubic centimetres of air does it contain? What is the surface area of the ball? (π = 3.14)

Given is that, diameter of the inflated ball (sphere) = 18 cm

⇒ Radius of the sphere = 18/2 = 9 cm

The amount of air that this ball contain is the volume of the sphere.

So, volume of sphere is given by

Volume = 4/3 πr³

Substituting value of radius, r = 9 cm in the above equation, we get

Volume = 4/3 × 3.14 × 9³

⇒ Volume = (4 × 3.14 × 9 × 9 × 9)/3

⇒ Volume = 9156.24/3

⇒ Volume = 3052.08

Surface area of the spherical ball is given by

Surface area = 4 πr²

⇒ Surface area = 4 × 3.14 × 9²

⇒ Surface area = 4 × 3.14 × 9 × 9

⇒ Surface area = 1017.36

Thus, volume of inflated ball is 3052.08 cm³ and surface area of inflated ball is 1017.36 cm².