Write an A.P. whose first term is a and common difference is d in each of the following.

a = 6, d = – 3

a = 6, d = – 3

Let a₁ = a = 6

Since, the common difference d = – 3

Using formula a_{n + 1} = a_n + d

Thus, a₂ = a₁ + d = 6 + ( – 3) = 6 – 3 = 3

a_{3 =} a₂ + d = 3 + ( – 3) = 3 – 3 = 0

a₄ = a₃ + d = 0 + ( – 3) = – 3

Hence, An A.P with common difference – 3 is 6, 3, 0, – 3…