Show that:

(i)

(i) let p(x) = 69 + 11x x2 + x3 and g(x) = x + 3


We have to prove that g(x) is factor of p(x)


So the zero of g(x)= – 3


P( – 3) = 69 + 11( – 3) ( – 3)2 + ( – 3) 3


= 69 – 69 = 0


Since the remainder is zero g(x) = x + 3 is factor of p(x)


(ii) Let p(x) = x + 2x3 – 9x2 + 12 and g(x) =2x−3


We have to prove that g(x) is factor of p(x)


So the zero of g(x)= 3/2



Since the remainder is zero g(x) is factor of p(x)


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