Using suitable identity, evaluate the following:

(i) 1033


(ii) 101 × 102


(iii) 9992


(i) (103)3

Given that: (103)3


= (100 + 3)3


= (100)3 + (3)3 + 3(100)23 + 3(100)32


[ (a + b)3 = (a3 + b3 + 3a2 b + 3ab2)]


= 1000000 + 27 + 90000 + 2700


= 1092727


(ii). Given that: 101 × 102


= (100 + 1) × (100 + 2)


= (100)2 + (1 + 2)100 + 1 × 2


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