Factorise the following:

(i) 9

(i) Given that: 9x² – 12x + 3

= 3(3x² – 4x + 1)

= 3(3x² – 3x − x + 1)

= 3[3x(x − 1) − 1(x − 1)]

= 3[(x − 1)(3x − 1)]

= 3(x − 1)(3x − 1)

(ii). Given that: 9x² – 12x + 4

= 9x² – 6x – 6x + 4

= 3x (3x − 2) − 2(3x − 2)

= (3x − 2) (3x − 2)