Factorise the following:

(i) 9

(i) Given that: 9x2 – 12x + 3


= 3(3x2 – 4x + 1)


= 3(3x2 – 3x x + 1)


= 3[3x(x − 1) − 1(x − 1)]


= 3[(x − 1)(3x − 1)]


= 3(x − 1)(3x − 1)


(ii). Given that: 9x2 – 12x + 4


= 9x2 – 6x – 6x + 4


= 3x (3x − 2) − 2(3x − 2)


= (3x − 2) (3x − 2)


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