Factorize the following:
(i) 1−64
(i) Given that: 1 – 64a3 – 12a + 48a2
= (1)3 + (−4a)3 + 3(1)2(−4a) + 3(1)(−4a)2
= (1 + (−4a))3
[∵ a3 + b3 + 3a2b + 3ab2 = (a + b)3]
= (1 – 4a)3
= 
= (2p)3 + (15)3 + 3(2p)2(15) + 3(2p) (15)2
= (2p + 15)3
[∵ a3 + b3 + 3a2b + 3ab2 = (a + b) 3]
32