Without actually calculating the cubes, find the value of:
(i). 
(ii). (0.2)3− (0.3)3 + (0.1)3
(i) 
Let a =1/2, b=1/3and c= −5/6
=0/6
= 0
⟹ (1/2)3 + (1/3)3 + (5/6)3
= 3 (1/2) (1/3) (−5/6)
= −5/12
[∵a3 + b3 + c3–3abc =(a + b + c)(a2 + b2 + c2 − ab− bc−ca)]
[ if
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