Six numbers from a list of nine integers are 7, 8, 3, 5, 9 and 5. Find the largest possible value of the median of all nine numbers in this list.

No of terms, n = 9

As, n is odd

Median is term.

⇒ Median is 5^th term

Let's first arrange given no in ascending order.

3, 5, 5, 7, 8, 9

Clearly, 9 is not possible as it is already at 6^th place and adding any term or terms can only shift its position ahead.

Also, 8 is possible if other three terms are greater than 8.

Therefore, 8 is the largest value possible.