If abc is a three digit number, then the number abc – a – b – c is divisible by


Since abc is a three digit number

General form of abc is abc = 100a + 10b + c


Now; abc – a – b – c = 100a + 10b + c – a – b – c.


abc – a – b – c = 100a – a + 10b – b + c – c.


abc – a – b – c = 99a + 9b.


abc – a – b – c = 9( 11a + b).


abc – a – b – c is divisible by 9 because 9 is one of its factor.


Hence the correct option is (a).

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