If x + y + z = 6 and z is an odd digit, then the three-digit number xyz is

Since the sum of the digits of xyz i.e x + y + z = 6

∴ By divisibility test of three the number xyz is divisible by 3.

Also the last digit (z) is odd digit.

∴ xyz is the odd multiple of three.

Hence the option (a) is correct.