Which of the following are APs? If they form an AP, find the common difference d and write three more terms.

-10, -6, -2, 2, . . .

For a series to be in AP, the common difference (d) should be

Equal.

D₁ = second term – first term = -6 – (-10) = 4

D₂ = Third term - Second term = -2 – (6) = 4

Since common difference is equal the above series is in AP

The next three terms will be the 5^th, 6^th, 7^th.

5^th term will be given by

= a + (5-1)d = a + 4d = -10 + 4(4) = 6

6^th term is a + (6-1)d = a + 5d = -10 + 5(4) = 10

7^th term is a + (7-1)d = a + 6d = -10 + 6(4) = 14