Which of the following are APs? If they form an AP, find the common difference d and write three more terms.

0, -4, -8, -12, . . .

For a series to be in AP, the common difference (d) should be

Equal.

d₁ = second term – first term = -4 – 0 = -4

d₂ = Third term - Second term = -8 – (-4) = -4

Since common difference is same the above series is in AP.

The next three terms will be the 5^th, 6^th, 7^th.

5^th term will be given by = a + (5-1)d = a + 4d = 0 + 4(-4) = -16

6^th term is a + (6-1)d = a + 5d = 0 + 5(-4) = -20

7^th term is a + (7-1)d = a + 6d = 0 + 6(-4) = -24.