Which of the following are APs? If they form an AP, find the common difference d and write three more terms.
,
,
…..
For a series to be in AP, the common difference (d) should be
Equal.
d1 = second term – first term =
–
= 0
d2 = Third term - Second term =
–
= 0
Since common difference is same the above series is in AP.
The next three terms will be the 5th, 6th, 7th.
5th term will be given by = a + (5-1)d = a + 4d =
+ 4(0) = ![]()
6th term is a + (6-1)d = a + 5d =
+ 5(0) = ![]()
7th term is a + (7-1)d = a + 6d =
+ 6(0) =
.