Which of the following are APs? If they form an AP, find the common difference d and write three more terms.

√3, √6, √9, √12


For a series to be in AP, the common difference (d) should be

Equal.


D1 = second term – first term = √3 - √6 = √3 (1 - √2)


D2 = Third term - Second term = √6 - √9 = √3 (√2 - 3)


Since common difference is not equal the above series is not in AP


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