Which of the following are APs? If they form an AP, find the common difference d and write three more terms.
√3, √6, √9, √12
For a series to be in AP, the common difference (d) should be
Equal.
D1 = second term – first term = √3 - √6 = √3 (1 - √2)
D2 = Third term - Second term = √6 - √9 = √3 (√2 - 3)
Since common difference is not equal the above series is not in AP