Find the sum of the following APs:
2, 7, 12, …., to 10 terms.
In the above series
First term (a) = 2
Common different (d) = n2 – n1 = 7 – 2 = 5
No. Of terms (n) = 10
The sum of the series is given by Sn = [ 2a + (n-1) d]
= [ 2×2 + (10-1)5]
= 245