Find the sums given below:
7 + 10
+ 14 +…. +84.
We have given a formulae to find sum of the series when first and last numbers are given.
Sn =
[2a + (n-1) d]
Where n is the last term in the series
d is the common difference
a is the first term.
an = 84, a = 7
d = n2 – n1 = 10
- 7 = 3.5
an = a + (n-1)d
84 = 7 + (n-1)3.5
77 = 3.5(n-1)
22 = n-1
n = 23
The sum of the series is Sn =
[2a + (n-1) d]
=
[ 2×7 + (2-1)3.5]
=
[ 91]
⇒
.