Find the sum of the first 40 positive integers divisible by 6.

Question

Philoid · Accepted Answer

The first 40 positive integers divisible by 6 are,

6, 12,…..240

Here we have n = 40 terms

First term (a) = 6;

Common difference is 6 since they are multiple of 6

The sum of 6 terms is given by (s_n) = [2a + (n-1) d]

S₆ = [2×6 + (40-1)6]

= 4920