Which term of the GP.

√3, 3, 3√3…… is 729?

First term (a) = √3

Common ratio (r)

n^th term in the GP (a_n) = ar^n-1

729 = √3×(√3)^n-1

3⁶ = √3ⁿ

Equating powers on both sides

= 6 ⇒ n = 12.