The 4^th term of a geometric progression is and the seventh term is Find the geometric series.

Given,

4^th term of the series =

ar³ =

a = ⇒ 1

7^th term of a series =

ar⁶ = ⇒ 2

Substituting ‘a’ in 1

× r⁶ =

r³ =

r³ = (³

equating power and base we will get

r =

The geometric series is a, ar, ar², ar³

,²,…..

, , , ,……