Find the area of the triangle formed by joining the midpoints of the sides of a triangle whose vertices are (0, – 1), (2,1) and (0,3). Find the ratio of this area to the area of the given triangle.
Let A (0, –1), B (2, 1) and C (0, 3) are the vertices of the triangle.
D, E and F are the mid–points of the sides AB, BC and AC respectively.

Mid – point formula = ![]()
Mid – point of AB ![]()
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D = (1,0)
Mid – point of BC = ![]()
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Mid – point of AC = ![]()
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Area of Δ ABC:
Area of triangle = ![]()
x1 = 0, x2 = 2 and x3 = 0
y1 = –1, y2 = 1 and y3 = 3
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ 4 sq. units
Area of Δ DEF:
Area of triangle = ![]()
x1 = 1, x2 = 1 and x3 = 0
y1 = 0, y2 = 2 and y3 = 1
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ 1 sq. units
Area of triangle ABC: Area of triangle DEF
4: 1