Find the slope and y–intercept of the line whose equation is

(i) y = x + 1 (ii) 5x = 3y (iii) 4x – 2y + 1 = 0 (iv) 10x + 15y + 6 = 0

The equation of the straight line with the slope (m) and y –intercept ‘c’ in the slope–intercept form is

y = mx + c

(i) here y = x + 1

⇒ slope of the line (m) = 1 and y–intercept ( c ) = 1

(ii) here 5x = 3y

3y = 5x

⇒

Thus the slope of the line = and y intercept ( c) = 0

(iii) 4x– 2y + 1 = 0

⇒ –2y = –4x –1

⇒

Thus the slope of the line (m) = 2

and y –intercept (c) = 1/2

(iv) 10x + 15y + 6 = 0

⇒ 15y = = 10x – 6

⇒

Thus the slope of the line (m) = and y –intercept (c) =