The sides of a right angle triangle PQR are PQ = 7 cm, QR = 25 cm and ∠Q = 90° respectively. Then find, tan P – tan R.
We have

We don’t need to find hypotenuse (PR) in the ∆PQR as tan θ = perpendicular/base.
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⇒ ![]()
And ![]()
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tan P – tan R = ![]()
⇒ tan P – tan R = ![]()
⇒ tan P – tan R = 576/175
Thus, tan P – tan R = 576/175